7^(4-3x)+31=50

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Solution for 7^(4-3x)+31=50 equation: 



7^(4-3x)+31=50

We move all terms to the left:

7^(4-3x)+31-(50)=0

We add all the numbers together, and all the variables

7^(-3x+4)+31-50=0

We add all the numbers together, and all the variables

7^(-3x+4)-19=0

We move all terms containing x to the left, all other terms to the right

7^(-3x+4)=19

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